Homework Answers
As segment Size = 4096 Byte so 12 bits will be used to represent the offset
Logical address or Virtual address
| segment No | offset |
Given Virutal address 2DAC0H
12 bit are used to represent offset so offset is AC0H (H for Hexadecimal)
Segment N0 = 2DH
Physical Address
| segment no | offset+Base |
Base corresponding to 2DH is BEEFH
so BEEFH + AC0 = C9AFH
=> overall physical address is 2DC9AFH
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