One string of a certain musical instrument is 80.0 cm long and has a mass of...
One string of a certain musical instrument is 80.0 cm long and has a mass of 8.79 g . It is being played in a room where the speed of sound is 344 m/s.
To what tension must you adjust the string so that, when vibrating in its second overtone, it produces sound of wavelength 0.756 m ? (Assume that the breaking stress of the wire is very large and isn’t exceeded.)
What frequency sound does this string produce in its fundamental mode of vibration?
Homework Answers
Frequency wanted is 344 / 0.756 = about 455 Hz
Wavelength of the 2nd overtone is 2 * 0.8 / 3 = 0.534 m
If the frequency is 455 Hz ( are you sure about that wavelength ?)
then
v = 455 * 0.53 = 242.97 m/s
V^2 = T / (m/l)
T = 59.03 * 10^3 * (8.79/.8) * 10^-3 = 650 N
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