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Question 3 tur mm Figure 2 Figure 2 depicts a circuit diagram featuring a source of EMF and four resistors with resistances a

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Answer #1

Using KVL in loop ABHIA

i1 R1 - E = 0

i1 = E/ R1

Using KVL in loop ABCDEFGHIA

i3 R3 + (i2 + i3) R4 = E

i3 (R3 + R4) + i2 R4 = E                                              eq-1

Using KVL in loop BCFGHB

i2 R2 + (i2 + i3) R4 - i1 R1 = 0

i2 R2 + (i2 + i3) R4 = E

i2 (R2 + R4) + i3 R4 = E                                            eq-2

Using KVL in loop CDEFC

i3 R3 - i2 R2 = 0

i3 = i2 R2 /R3                                                         eq-3

Using eq-2 and eq-3

i2 (R2 + R4) + ( i2 R2 /R3  )R4 = E  

i2 (R2 R3 + R4 R3 + R2 R4) = E R3

i2 = E R3 /(R2 R3 + R4 R3 + R2 R4)

using eq-3

i3 = i2 R2 /R3

i3 = (E R3 /(R2 R3 + R4 R3 + R2 R4)) (R2 /R3)

i3 = E R2 /(R2 R3 + R4 R3 + R2 R4)

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