Question

Shown in the figure below is an electrical circuit containing three resistors and two batteries. R 13 10 R2 + 12 R1 4 I Write down the Kirchhoff Junction equation and solve it for Ij in terms of Iz and 13. Write the result here: 11 = Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and follows the perimeter of the circuit diagram clockwise. Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and touches the components Ry, 10V, R7, and 4v. 0 = The resistors in the circuit have the following values: . Ry=80 • R2=40 Rg=1.2 Solve for all the following (some answers may be negative): I1 = Amperes Iz = Amperes 13 = Amperes NOTE: For the equations, put in resistances and currents SYMBOLICALLY using variables like R1,R2 R3 and 11,12,13. Use numerical values of 10 and 4 for the voltages.

Answer 1

R3 10 R ho Atjunction 13 I t Iz = 12 11 -Izt Iz=0 It В Ja II = I2-13 3 Ri AIL u A 4 KVL an loog ALDEA IIRI+Iz R3+4=0 -6 Ist Iza-4 KUL an doop ABEFA -6 1 - 412+14=0 - I Ri +10-12 R2 +420 -611-4I2 = -14 Solving 0) (1) I = 0.88 A I2 = 2.18 A Iz=1.29 Am