Question

please answer by steps so i can understand, thank you in advance

QUESTION 7 The average moviegoer sees 8.5 movies a year. A moviegoer is defined as a person who sees at least one movie in a theater in a 12-month period. A random sample of 40 moviegoers from a large university revealed that the average number of movies seen per person was 9.6. The population standard deviation is 3.2 movies. At the 0.05 level of significance, can it be concluded that this represents a difference from the national average ? Step 1: State hypotheses by filling in the symbol ( <> or not equal) and the population mean: HoH HT: Step 2: Find the critical value (from the table) (example: 2.34 or -2.34 or +/- 2.34) Critical z value is: Step 3: Compute the test value using the formula (round to two decimal places, example 6.45): Z test value is: Step 4: Reject the null or do not reject the null(type in either Reject the null or do not reject the null only): Step 5: Conclusion sentence (type in either is or is not only to reflect what you found): There enough evidence to support the claim that the mean number of movies a moviegoer sees in a theater per year is different from 8.5.

Answer 1

het xbeat number of movies a moviegoer I sees na theater per year. - x = 9.6 n = 40 r = 3.2 a population standard clenation Hese population standard deviation is known we use 2- test step 0 state hippothesis To test that the mean number of movies a moviegoersees in a theater per year in diff esent from 8.5 Ho: ll - 2.5 Hi: elt 8.5 step 2 find the critical reclue a 20.05 critical zoveele = Zx12 20.025 critreal 2-value = +1 -1.96 I . Step 3 test statistic test est - - oli g. 6 - 8.5 3.2 Tho Z test - 2017 or z test vetive = 2017

Step 4 Deciston Here & I Caitical z-value = 1.96 < 2test = 2.17 1. Reject promull Hypothesis Step 6 Conclusion :- The is enough evidence to support the chum that the mean number of movies a moviegoer sees in a theater per year e 13 different from 8.5