Question

Question 2 of 10 (1 point) View problem in a pop-up The average "moviegoer" sees 8.5 movies a year. A moviegoer is defined as a person who sees at least one movie in a theater in a 12-month period. A random sample of 46 moviegoers from a large university revealed that the average number of movies seen per person was 10.1. The population standard deviation is 3.2 movies. At the 0.05 level of significance, can it be concluded that this represents a difference from the national average? Source: MPAA Study. Part 1 x State the hypotheses and identify the claim with the correct hypothesis. Ho: 8.5 claim H1: u 8.5 not claim This hypothesis test is a one-tailed test. Correct answer: 8.5 not claim 8.5 claim two-tailed Part 2 out of 5 Find the critical value(s). Enter the values in ascending order and round the answers to two decimal places. Critical values are and Tutorial help

Answer 1

Answer:

Given,

Ho : u = 8.5

Ha : u != 8.5

Here it is two tailed test

Z critical values are - 1.96 & 1.96 [since from standard normal table]

test statistic z = (x - u)/(s/sqrt(n))

substitute values

= (10.1 - 8.5)/(3.2/sqrt(46))

= 3.39

Z critical = 1.96

P value = 0.0006989 [since from z table]

= 0.0007

Here p value < alpha, so we reject Ho.

So there is sufficient evidence to support the claim.