Please explain step by step,
thank you so much!
a) True
b) As item#1 is of same weight as item#5 but its value is less than item#5 so to make maximaum value we will take item#5 always instead of item#1.
c) F(10) = 20
d) For maximum profit we have to pick 5 item#5 so total profit will be 5*4=20.
e) Bib-Oh time complexity will be O(W*N).
Please explain step by step, thank you so much! 0-1 Knapsack (N=6, W=10) Item Weight Value...
Solve the 0-1 knapsack problem given the following items, each labeled with weight and value. Assume the total weight limit W is 8 lbs. Item 1 Value ($) 8 Weight (lb) 1 23 4 40 30 54 2 6 3
In weighted knapsack problem, given the knapsack capacity is 16 and the following items (Weight, Value), what is the maximum value we can take away. Explain shortly how and by what approach you arrived at this solution. Item 1 (4, 12) Item 2 (3, 14) Item 3 (7, 22) Item 4 (8, 32) Item 5 (4, 24) Item 6 (6, 20)
Design a local search algorithm for the 0-1 knapsack problem. Assume there are n items x1 ... xn each with weight wi and value vi. The knapsack can have at most one of each item and the total weight cannot exceed W. You want to maximize the total value in the knapsack.Question 1: (7 points) Show the psuedocode/explanation for your algorithm.Question 2. (3 points) Is it guaranteed to find an optimal solution? Justify your answer.
5) (10 pts) Greedy Algorithms The 0-1 Knapsack problem is as follows: you are given a list of items, each item has an integer weight and integer value. The goal of the problem is to choose a subset of the items which have a sum of weights less than or equal to a given W with a maximal sum of values. For example, if we had the following five items (each in the form (weight, value)): 11(6, 13), 2(4, 10),...
Haloo , i have java program , Java Program , dynamic program Given a knapsack with capacity B∈N and -n- objects with profits p0, ..., p n-1 and weights w0, ..., wn-1. It is also necessary to find a subset I ⊆ {0, ..., n-1} such that the profit of the selected objects is maximized without exceeding the capacity. However, we have another limitation: the number of objects must not exceed a given k ∈ N Example: For the items...
please I would like assistance with this which are question 1
and 2, thank you
2. We have 5 objects, and the weights and values are No. 2 3 4 5 10 20 30 50 V 20 30 66 60 55 W 40 The knapsack can carry a weight not exceeding 90, find a subset items and give the total weight and value for following algorithms: 1) By using the algorithm of greedy of value for 0-1 knapsack problem? By...
Fill out the table for the knapsack problem, where the objects, weights, and values are as given, and the overall weight limit is 10 Next, circle the entries in the table that are used when backtracking to find objects to use in the solution Then list the object numbers that can be used for an optimal solution .Also list the weights and values of those objects Verify that the values of your solution objects add up to the optimal number...
(2) (15 points) Use the Best-First Search with Branch-and-Bound Pruning algorithm for the 0-1 Knapsack problem to maximize the profit for the following problem instance. Show the actions step by step. Pi wi 1 $20 2 10 2 $30 5 6 3 S35 7 5 4 $12 3 4 5 $3 3 wi W 13
1) Use the Breadth-First-Search with Branch-and-Bound Pruning
algorithm for the 0–1 Knapsack problem to maximize the profit for
the following problem instance. Show the actions step by step.
2) Use the Best-First Search with Branch-and-Bound Pruning
algorithm for the 0–1 Knapsack problem to maximize the profit for
the following problem instance. Show the actions step by step.
i PiPi 1 $20 210 2 $30 5 6 3 $35 75 4 $12 3 4 5 $3 13 wi Wー13
1. Apply the dynamic programming algorithm discussed in class to solve the knapsack problem. (10 points) a. Show the completed table. b. Which items are included in the final configuration of the knapsack? c. What is the maximum value that can fit in the knapsack using a configuration of these items? item 1 2. 3 4 weight 3 2 value $25 $20 $15 1 capacity W = 6. 4 5 $40 $50 5