Question

A person walks due south from point A for 500 yards and then due west for 300 yards, arriving at point B. Answer the following questions using complete sentences. 2 points for each correct answer and 2 points for each correct explanation. i. What is the person's displacement from the starting point? How did you calculate this? Be sure to round to the nearest hundredth. ii. From point B, in what direction would the person have to look in order to be looking back at point A (the starting point)? Give your answer as a true bearing calculated to the nearest hundredth of a degree. Explain how you got this answer. iii. A friend is standing at point A looking at point B.In what direction would that friend be looking? Give your answer as a true bearing calculated to the nearest hundredth of a degree. Explain how you got this answer.

Answer 1

i) ACB is the patch now, AACB is a right angle A. So, be can apply Pythagoras Theorem (AB)² = (Ac)²+(BC) 3 AB? = (500) H300)2 - 250000 +90ooo 500 yards gooo 300 yards as AB = 340000 AB= 100034 AB = 583 yards Displacement is the shortest distance between two points. So, person's displacement from point A = AB =583yards Rounding to nearest hundredth = 600 yards. ii) Let LB=0 tan o = Perpendicular Base O= tan! (2/2) 0 - 59° = 60° Bearing = N(90-0)°E = N(90-603E = N30°E

lini) kan (LA) - BC. come AC tam (LA) = 3 LA= tant (2) = 30.96 LA ~30] Beasing is s ow
. I hope you have got your answer , if you need any further clarification in any step, please let me know through comment.