SOLUTION :
|5x + 1| ≥ 4
=> (5x + 1) ≥ 4. or - (5x + 1) ≥ 4
=> 5x ≥ 3 or - 5x ≥ 5
=> x ≥ 3/5 or - x ≥ 1
=> x ≥ 3/5 or x ≤ - 1
=> (- ∞, - 1] U [ 3/5, ∞) in interval notation (ANSWER).
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