Question

Find the exact value of the indicated trigonometric function of e. Find sec. 10) sin 0 - - $, tan e > 0 11) tan 0 =-, in quadrant I Find cose.

Answer 1

ahal U 107 Sino =-8 , tan o>o , find seco est quadrant for learning this there is a trick : coseco All positive * Add) Sugar to Coffee) Sino tano coto C080 seco Sinot x Š tanat & coto - coso seco 0 Here tomo is greater than o, so it is positive .. value of tand is positive only in 1st and god quadrant, but since sino is negative, o must not lie in est quadrant. So @ must lie in 3rd quadrant Now & sino = - 8 perpendicular (P) Hypotenuse (H) . 2 l puthaar thagoras theorem ...P28, H=9 Now Base (B) - JH² - P2 B = √81-64

Hypotenuse . Seco - Base regative sign implies that o lie in 3rd quada -orant and in zoel quadrant Seco is negative * Se 0 - - 9 11 117 tano =- 2 o in quadrant Il find caso. - Perpendicular (?) Since we know that tano - Base (B) p=2 , B= 7 Applying pythagoras theorem H = JP²+ B² (4+49 i coso = B H =- 7 since o lies in quadrant Il, caso must be negative. So, Icoso = - 7