Solution:
Given that,
= 0.5
1 - = 1 - 0.5 = 0.5
margin of error = E = 5% = 0.05
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 =
2.576
Sample size = n = ((Z / 2) / E)2 *
* (1 -
)
= (2.576 / 0.05)2 * 0.5 * 0.5
= 663.5776
= 664
n = sample size = 664
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