Force in a magnetic fieldHomework Answers
Part A)
F = qvB
F = (6)(1.6 X 10-19)(10.5 X 103)(.3 X 10-4)
F = 3.02 X 10-19 N
Part B
qvB = mg
(6)(1.6 X 10-19)(v)(.3 X 10-4) = (1.9939 X 10-26)(9.8)
v = 6.78 X 10-3 m/s
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Force in a magnetic field
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