Here this is the difference table is given below, with average difference and standard deviation of paired differences.
Pair | Male | Female | Difference(d) |
1 | 29300 | 29000 | 300 |
2 | 31500 | 31600 | -100 |
3 | 30400 | 29800 | 600 |
4 | 28500 | 28500 | 0 |
5 | 33500 | 32600 | 900 |
6 | 27800 | 28000 | -200 |
7 | 29500 | 29200 | 300 |
8 | 31200 | 30100 | 1100 |
Average | 362.5 | ||
Std. Dev. | 471.8883 |
(a) HEre n = 8
dF = 8 - 1 = 7
confidence level = 0.05
test is two tailed as it is two tailed hypothesis.
tcritical = TINV(0.05, 7) = 2.3646
so here we would reject the null hypothesis when the test statistic
t < -2.3646 or t > 2.3646
(b) Here average difference = = 362.5
standard deviation of difference = sd = 471.8883
standard error of difference between means = sed = sd/sqrt(n) = 471.8883/sqrt(8) = 166.8377
Test statistic
t = /sed
= 362.5/166.8377 = 2.173
(c) so here t < tcritical so we would fail to reject the null hypothesis and conclude that there is no significant difference between salaries of males and females.
. An experiment is conducted to compare the starting salaries of male and female college gradua...