A binormal experiment has 6 trials in which p = 0.25. What is the probability of getting at least 3 successes?
0.8965
0.0104
0.1005
0.1694
p = 0.25
n = 6
P(X > 3) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)
= 6C3 * 0.253 * 0.753 + 6C4 * 0.254 * 0.752 + 6C5 * 0.255 * 0.751 + 6C6 * 0.256 * 0.750
= 0.1694
Option-C) 0.1694
A binormal experiment has 6 trials in which p = 0.25. What is the probability of getting at least 3 successes?
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