Find the maximum possible area of a rectangle in quadrant 1
under the curve y = (x − 6)^2. (Include
a test showing that your rectangle’s area is the maximum
possible.)
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Find the maximum possible area of a rectangle in quadrant 1 under the curve y =...
10. (5 points) You want to maximize the area of an inscribed rectangle under the line 4 in the FIRST quadrant with the x-axis and the y-axis. Find the measurements of such rectangle so that you can have maximum area. Please draw the picture of the problem on X-y coordinate system to receive full credit. Yx) = -x +
2. The area of a rectangle with vertices (±x, ±y) is 4xy. Use Langrange multipliers to find the maximum area of such a rectangle with vertices on the ellipse 4x 2 + y 2 = 32 2. The area of a rectangle with vertices (trty) is 4xy. Use Langrange multipliers to find the maximum area of such a rectangle with vertices on the ellipse 412 + y2-32. 2. The area of a rectangle with vertices (trty) is 4xy. Use Langrange...
under the Curve 2. Let y e2". a) Using 4 rectangles of equal width (Δ 1)and the rightendpoint of the subinterval for the height of the rectangle, estimate the area under the curve on the interval [0,4]. Then sketch a graph of the function over the interval along with the rectangles. b) Using 4 rectangles of equal width (Ax 1)and the left endpoint of the subinterval for the height of the rectangle, estimate the area under the curve on the...
Peer Leading Exercise 7 Spring 2019: Area Under the Given a function (x), the area under the curve is the area of the region bordered by the x -sxis and the graph of y(x). Area under the curve is somehow related to anti-derivatives. We wish to Example: Let f(x) -10-2x. Find the area under the curve between x 0 and x graph to help you visualize what is going on. Do you recognize the shape? 5. We include a 2...
Find the maximum area of a triangle formed in the first quadrant by the x-axis, y-axis, and a tangent line to the graph of y = (x+1)^-2
Find the area of the region y that lies under the given curve y = f(x) over the indicated interval a <x<b. 2 Under y = 8x e over 0 < x < 2 2 over 0 < x < 2 is Round your answer to six decimal 2 The area under y = 8x e * places.
296. Area under a curve. The area of the region bounded by the curve y = (-2<x< 2), the x-axis, V4 - x4 V4- and the lines x = a and x = b(a < b) is given by sin - €) - sin-"). a. Find the exact area if a 1 and 1 b. Find the exact area if a = -V3 and 5 = vā.
Find the area under the curve y = 25/x3 from x = 1 to x = t. Evaluate the area under the curve for t = 10, t = 100, and t = 1000. t = 10 t = 100 t = 1000 Find the total area under this curve for x > 1.
1 point) Find the area under the curve y = 1/(6x3) from x = 1 to x = t and evaluate it for t = 10,t = 100. Then find the total area under this curve for x > 1. a) t = 10 b) t = 100 c) Total area
(1 point) Find the area under the curve y = 1/(4x) from x = 1 to x = t and evaluate it for t = 10, t = 100. Then find the total area under this curve for x > 1. (a) t = 10 99/800 (b) t = 100 9999/80000 (c) Total area 1/8