Question

1

Let X denote the amount of space occupied by an article placed in a 1-ftpacking container. The pdf of X is below. F(x) = {72x

Obtain the cdf of X. x < 0 0<x<1 F(x) = { X> 1

(b) What is P(0.7) [i.e., F(0.7)]? (Round your answer to four decimal places.) (c) Using the cdf from (a), what is P(0.45 < X

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Answer #1

August TUESDAY f(x) = lo The pdf of the amount of space is given as- f(x) = { 7 2 x *(1-x) olaci Therefore the cdf of X is gi

WEDNESDAY 00 00 - Since it is a continuous dicth, probability of a particuler point is zero. Therefore Plass X207) = P/ 0.45

August THURSD Ox = {1x2) - € 68) = 0.654 - (0-8) = 0.0145 8x = √ 0.0145 = 0-120 Now mean y = 0.8 ,sd x = 0.120 P[ X24+0x] - P

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