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Let X denote the amount of time a book on two-hour reserve is actually checked out, and suppose the cdf is the following. 0x<

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Answer #1

Find these probability using property of distribution function

F(X>a) =1-F(X<=a),

F(a<=X<=b)=F(X<=a) - F(<=a)

Probability density function =derivative of CDF

E(X) = integration of X. f(x)

Where f(x) =probability density function

V(X) =E(X^2)-(E(X))^2

Ans

A) 0.25

B) 0.109

C) 0.609

D) median check out duration is 3.464

F) E(X) =2.67

G) V(X)=0.871, standard deviation =0.933

H) h(x) =X^2

E(h(x))=8

Solution file is attached go through it

I hope you clarify this concept

© P(x725) = 1- P(x22.5) Using property of CDF F(x79) = |- FlyLa) / MX<2.5=122725 116 lo P(x22:5)= 6.25 lup get P(1725) = 1+(2we get d. f(n)) = f(n) flows after clestradine M20 tal- d (172) Ounay 4 LH Id 1 an el Consetempt = 2120 Tn HLO f(n) = q anh oSince v(x)= E(X2) - (E(x)? V(x)= 8~(2167)2 = 8- 7.129 = 0.87/ V(x) = 0.871 Stenelard deviatime = v = rrex) = V0.87) -0.933 He

Thanks

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