Question

How many mL of 0.115 M sodium hydroxide would it take to neutralize 5.00ml of 0.550 M hydrochloric acid? Show all steps and explain (Do not use formula M1V1=M2V2)

Answer 1

One equivalent of NaOH is react with one equivalent of HCl to neutralize it. NaOH + HCl -----> NaCl +H_{​​​​​​2}​​​​​O

So one mole of sodium hydroxide is neutralize the one mole of HCl, so we have to find out number of moles of HCl.

Molarity of HCl is 0.550M (given)

and Molarity of NaOH is 0.115M (given)

See handwritten answer for calculation :-

Hope it helps you.