Question

Determine whether the graph of the polar equation is symmetric with respect to the horizontal axis, the vertical axis, or the
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Answer #1

We have given the polar coordinates so we firstly transform it into the Cartesian coordinate.

We know in general that

x=rcos\theta;y=rsin\theta;x^2+y^2=r^2

So we will have now

r=2+3cos\theta

Will be now

\sqrt{x^2+y^2}=2+3\frac{x}{r}

Which will be now

\sqrt{x^2+y^2}r=2r+3{x}

{x^2+y^2}=2\sqrt{x^2+y^2}+3{x}

{x^2+y^2}-3x=2\sqrt{x^2+y^2}

On square both sides

({x^2+y^2}-3x)^2=4({x^2+y^2})

To check the symmetry we take the point on the graph as

(x,y)

So

({x^2+y^2}-3x)^2=4({x^2+y^2})

And now if we take (x,-y) so it will be

({x^2+(-y)^2}-3x)^2=4({x^2+(-y)^2})

({x^2+y^2}-3x)^2=4({x^2+y^2})

The equation will remain same

So the graph has the symmetry about x axis (horizontal axis)

So first option horizontal axis is correct answer

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