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Transform the circuit below to a simple Thevenin circuit (show all steps) (Remark: the load is already removed): A 2 ko iko R
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Answer #1

1- Given cercuit is lkn QkN i k isv Ika 2 KN in Vth wro the m IKN ot 15v © {aka a volrage divider rule TRARL th= 2KN XISN s aM LUN Crew)||( 2kw) 1 - 2012 KN s IKN 2 2 KNE I Kn 2+2 9 Roth aku The Thevenin circuit will be as Rith mm akn OA r Rih qwth B

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