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Data for gas mileage (in mpg) for different vehicles was entered into a software package and part of the ANOVA table is shown

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Answer #1

Solution:

We have

F = MS vehicle / MS error

F = 364/13.73

F = 26.51129

df1 = 5

df2 = 15

So, required p-value by using F-table or excel is given as below:

P-value = 0.000000604272

P-value = 0.0000

Answer: C) 0.0000

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