Question

Η week #4 • Homework2. Find Rab 1.8kΩ 1.8kΩ 1.8kΩ 1.8kΩ 1.8kΩ , 1.8kΩ 1.8kΩ ΑΛΛ, 1.8kΩ 1.8kΩ Korea Aerospace University

Answer 1

ERR=R_ - Reli8kr with KAL=RG КЕЛ Rq .: : . Ry → Resistors R, & Re are in series obtained equivalent resistance to Resistance R and the is in parallel RT; = (R1+R2) /| R3 iz (1.8K+18k) 11.0.8k) (3.6K)CI:8k) :53:66 +1.8K · =1.2K12 → Redraw the circuit. . T 2 ks . . 2381 Mes sha Lugk3=R6 SYR SM --- MW- 1.8K2 Ry=1.8KR

: Now use s-Y transfomation technique The dotted lines, indicates the transformed y Connection. , R4 R8 - 11.8K) (li8k) Ret Ret Rq (lisk HiClifk)+(1.8k) Ri=6002 since, all resista values are same then same ' value obtains for remaining resistors. B = 6000 . R² = 6000 fd second s-y foranstalmation lly Ra= 6000 Rb - 6001 i RC = 6oor → Redraw the circuit. 1. 2km Ra=6oor. DON ms=6001 GOO 2

→ Now, Ri i Ra and Ry, are in series Prz = Rit Ratry, = 600+600+1.2K = 2.4kn - Resistors Rs and Rb are in series Rīga Rot Rb = 600+600 = 1-2k1 R12=2.4K2 Re=60or 6002 RT3=12K2 ob à Resistors RF and Riz are in parallel Razia (Rtg)(R13) (2:43)(132K) . RT₂+ RT3 2.4K+12K . RT4 = 8oor R RT4 . a! 6oor soon Goor tb. Rab = R +RT, TRC = 600+800+600. Rab = 2 kg