Solution:- Whole solution is shown in below images.
Part (a) :- First of all find the elongation of the member due to tensile load (P) and due to change in temperature (∆T) separately. The final total elongation of the member is equal to the sum of the elongation due to load and the elongation due to change in temperature.
The elongation of the member is obtained as 1.3742 inches.
Part (b) :- First of all find the moment of inertia of the symmetrical I- section about the horizontal axis at the centroid. Substitute the respective values in the given formula to find the maximum bending tensile stress of the cross-section.
The maximum tensile stress is obtained as 33.1 Ksi.
Part (c) :- First of all find the reaction at support in the simply supported beam and then from the shear force diagram, find the corresponding maximum shear force (Vmax) value. Now, the maximum shear stress of the rectangular cross-section is 1.5 times the average shear stress. Substituting all the respective values, find the maximum shear stress.
The maximum shear stress obtained is 18.7 Ksi.
A force and a temperature change were applied to a member. What is the elongation of...
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For the beam and loading shown, determine: A. The maximum shearing force in the beam = kips B. The maximum bending moment in the beam = kip in C. The centroid of the cross section is at (in.) from the bottom b D. The moment of inertia of the cross section = in^4 E.the shearing stress at point a = ksi F. The shearing stress at point b = ksi G. The max shearing stress in the cross section =...
(7) A moment of M = 4 kip-ft is applied on the cross section shown. Determine (a) the normal stress at point a, (b) the maximum tensile and compressive bending stresses in the beam. Ans: (a) oa = 0.0523 ksi (b) om =-1.779 ksi, om' = 3.72 ksi 10.5 in.al -3 in. +0.5 in. 0.5 in. B 3 in. M 10 in. D +0.5 in.
Asap 4. Steel members AB and AC have Cross-section with the dimensions shown the rectangular 29.0 X 103 ksi; ơys 50 ksi. a) Determine which member (AC or AB) is a candidate 1.5 in. С 1.5 in. for buckling: and then determine the maximum load P th e frame can support such that buckling does not 2.5 in occur with respect to the y-axis, nor with respect to the z-axis. Treat the end conditions as pinned at both ends for...
***please be as accurate as possible this is extra credit because we did bad on test*** Determine the maximum shear stress in ksi to the nearest 0.1 ksi. P b a = 3 ft b= 4 ft C= 3 in d = 9 in P = 321 kip
For the tension member shown below, determino the maximum tenslon force Tu that ma applied and meet the following requirements of the AISC Manual: (s P a. Tensile Yielding 1. b. Tensile Rupture c. Bolt Shear d. Bearing at Bolt Hole 1-1'4 A35 GusseT L16 (ASTAM A30) L6XYK AS1M A36 MA1'L GAEE 31 For the tension member shown below, determino the maximum tenslon force Tu that ma applied and meet the following requirements of the AISC Manual: (s P a....
The flanged member shown below is subjected to an internal axial force of P = 6500 lb, an internal shear force of V = 4500 lb, and an internal bending moment of M = 19200 lb-ft, acting in the directions shown. d M Iw y HI a y Ilk thu The dimensions of the cross section are: bf = 8.0 in. tp = 0.61 in. d = 11.0 in. tw = 0.38 in. The cross-sectional area of the flanged shape...
1-Determine the % elongation, yield stress and ultimate tensile strength of the material tested above 2-Calculate the elastic modulus of the material tested above 3-If a 200mm cylindrical rod of the material tested above, with radius 20mm, was subjected to a tensile load of 200kN, what would the length be? 4-An underground wastewater steel pipe with 2mm walls carries an ammonia solution of 40 g/m3. The pipe is in contact with groundwater (assume 0 g/m3 ammonia). Determine the diffusion rate...
The answer to a is NOT 2.37 in. The hint is " The applied load does not act at the section centroid. The loading is then eccentric, bending moments are generated about the x and z axis, and the stress is the superposition of the axial and two bending stresses. Locate the point of max compressive stress and write the max stress equation in terms of a. Solve this equation using that stated allowable compressive stress." Do not round intermediate...
A tee-shaped flexural member is subjected to an internal axial force of P = 4,000 N, an internal shear force of V = 3500 N, and an internal bending moment of M = 1770 N-m, as shown. If the moment of inertia about the z axis is 8,840,000 mm4 and the centroid of the section is located 95 mm above the bottom surface of the beam, determine the normal stress σy at point H. -0.412 MPa -0.615 MPa 0.000 MPa...