A compound is found to consist of 29.4 % Ca, 23.5 % S, and 47.1 %...

Question

Question

A compound is found to consist of 29.4 % Ca, 23.5 % S, and 47.1 % O by mass. What is the empirical formula of this compound?

Answer 1

Answer #1

Let the total mass of compound be 100 g

we have mass of each elements as:

Ca: 29.4 g

S: 23.5 g

O: 47.1 g

Divide by molar mass to get number of moles of each:

Ca: 29.4/40.08 = 0.7335

S: 23.5/32.07 = 0.7328

O: 47.1/16.0 = 2.9438

Divide by smallest to get simplest whole number ratio:

Ca: 0.7335/0.7328 = 1

S: 0.7328/0.7328 = 1

O: 2.9438/0.7328 = 4

So empirical formula is:

CaSO₄

Answer 2

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