![Given the following data set, estimate the value of Km [Substrate] Reaction Rate (mm) (uM/min) A. 4 mM B. 9 mm C. 79 mm D. 13](http://img.homeworklib.com/questions/01cd9d80-667f-11ec-878f-177b0595ceae.png?x-oss-process=image/resize,w_560)
Homework Answers
![MO In the plot No Vo [s], maxim note = Umax. . Here, Unax = 138 Lumax = 138 = 69 Vnex = 69 by graph, 69 valtion rate (vo) giv](http://img.homeworklib.com/questions/4a0a4f20-667f-11ec-bf1c-45c569c0c8dd.png?x-oss-process=image/resize,w_560)
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Given the following data set, estimate the value of Km [Substrate] Reaction Rate (mm) (uM/min) A....
a. An enzyme has a Vmax of 100 umol/min and a Km of 40 uM. When...
a. An enzyme has a Vmax of 100 umol/min and a Km of 40 uM. When substrate concentration is 40 uM what is the initial reaction rate? b. An enzyme with a Vmax of 100 umol/minute and a Km of 10 uM was reacted with a irreversible active site specific inhibitor. After reaction with the inhibitor, the enzyme was assayed using a 2 mM concentration of substrate, and it gave a reaction rate of 20 umol/min. What percentage of the...
Values for an Enzyme and a substrate are: Km=4 uM and kcat=20/min. For an experiment where...
Values for an Enzyme and a substrate are: Km=4 uM and kcat=20/min. For an experiment where [S]=6mM, it was found that Vo=480nM/min. What was the enzyme concentration? Give your answer in nM. Using the same kcat and Km as the previous question, if [Et]=0.5uM gives a Vo=5 uM/min, what wat the [S]? Give your answer in uM. reaction is run with the kcat=20/min and the Km=4uM. Use the enzyme concentration from question 1 above. A very strong inhibitor is added creating...
A different experiment yields the following kinetic data Substrate] (mM)Vo (uM/min) no inhibitorVo (uM/min)+7 nM inhibitor...
A different experiment yields the following kinetic data Substrate] (mM)Vo (uM/min) no inhibitorVo (uM/min)+7 nM inhibitor 0.02 0.04 0.10 0.25 1.00 2.50 0.8 2.9 8.6 24 36 50 Plot the data for the kinetics of the enzyme (with and without the inhibitor) in a double reciprocal (Lineweaver-Burk) plot. Keep in mind that the x axis is 1/[S] and the y axis is 1/Vo. If you are using Excel you want to choose the (x,y) scatter plot (without a ne). You...
Name Page Number Date Vmax 1. Estimate Vmax and Km using the velocity vs. substrate concentration...
Name Page Number Date Vmax 1. Estimate Vmax and Km using the velocity vs. substrate concentration plot - KM 2. Calculate the Vmax and Km using the Lineweaver-Burk plot. KM Vmax (S), uM 0.08 0.12 0.54 1.23 1.82 2.72 Reaction Velocity (UM/min) 0.15 0.21 0.70 1.1 1.3 15 4.94 10.00 1.8
The value of Km for the shown data for a hexokinase-catalyzed reaction is with the unit...
The value of Km for the shown data for a hexokinase-catalyzed reaction is with the unit of . The value of Vmax for. the same reaction is with the unit of . Be sure to give the values with the correct number of significant figures. You might have to construct a kinetic plot. For units, choose one answer from (uM, 1/ UM, HM/second, uM x second, mM, 1/mM, second, 1/second, mM/second, mM x second) vo (mM/sec) Glucose concentration (mm) 0.10...
help with b) please 3. Use we wyl Reaction rate (mol/min) (Substrate] Substrate Substrate + Unknown...
help with b) please
3. Use we wyl Reaction rate (mol/min) (Substrate] Substrate Substrate + Unknown 1/[Substrate) 1N 1N (s. wow (UM) 0,055 0.1 I I 18.19 10 (2.5 10.115 0.183 0.4 8.70 5.46 5 10.17 0. 25 0 .2 5.884 0.250 .306 0. 1 4 3.29 20 0.31 0.35 0.05 3.23 2.86 SIOPE (r-oris) 10 12 -0.4 02 00 02 04 06 08 substrate b) Find Km and Vmax. Show your work. 16
(15 points) The following data is for a reaction catalyzed by tyrosine monoxygenase: Substrate Concentration (mol/L) ...
(15 points) The following data is for a reaction
catalyzed by tyrosine monoxygenase:
Substrate
Concentration
(mol/L)
Initial Velocity (mM/min)
1.5
0.66
1.2
0.65
0.81
0.45
0.65
0.39
0.49
0.32
0.27
0.21
a) Plot the velocity (y-axis) versus substrate
concentration [S] (x-axis) curve and insert/draw the graph in the
space below. What are the approximate KM and
Vmax values?
b) Construct a 1/v (y-axis) versus 1/[S]
(x-axis) plot in the space below. Calculate the KM and
Vmax values.
c) Calculate the...
1. The turnover number for an enzyme is known to be 5000 min. From the following set of data, calculate the Km, Vma...
1. The turnover number for an enzyme is known to be 5000 min. From the following set of data, calculate the Km, Vmax and the amount of enzyme present in this experiment. Use excel to obtain the lineweaver burk plot. Substrate concentration (MM) 1 Initial velocity (umol/min) 167 250 334 376 498 499 100 1,000
CHEM3250 Assignment-Enzyme Inhibition Consider the data below for an enzyme catalyzed reaction. T...
CHEM3250 Assignment-Enzyme Inhibition Consider the data below for an enzyme catalyzed reaction. The rate of the reaction has been determined with and without an inhibitor. A total concentration of enzyme of 20 uM was used in the experiment. SHOW WORK AND UNITS!!! Without Inhibitor With Inhibitor [substrate] (mM)Rate of formation of te of formation of product product (mM/min) mM/min) 6.67 5.25 0.49 7.04 38.91 1.0 2.2 6.9 41.8 44.0 1.5 3.5 1 a) On the same graph, plot the data...
54. What is the catalyze reaction rate? Km=2 mM Kcat= 3 s-1 At the enzyme concentration=10...
54. What is the catalyze reaction rate? Km=2 mM Kcat= 3 s-1 At the enzyme concentration=10 nM and substrate concentration= 3 mM
A different experiment yields the following kinetic data Substrate] (mM)Vo (uM/min) no inhibitorVo (uM/min)+7 nM inhibitor 0.02 0.04 0.10 0.25 1.00 2.50 0.8 2.9 8.6 24 36 50 Plot the data for the kinetics of the enzyme (with and without the inhibitor) in a double reciprocal (Lineweaver-Burk) plot. Keep in mind that the x axis is 1/[S] and the y axis is 1/Vo. If you are using Excel you want to choose the (x,y) scatter plot (without a ne). You...
Name Page Number Date Vmax 1. Estimate Vmax and Km using the velocity vs. substrate concentration plot - KM 2. Calculate the Vmax and Km using the Lineweaver-Burk plot. KM Vmax (S), uM 0.08 0.12 0.54 1.23 1.82 2.72 Reaction Velocity (UM/min) 0.15 0.21 0.70 1.1 1.3 15 4.94 10.00 1.8
The value of Km for the shown data for a hexokinase-catalyzed reaction is with the unit of . The value of Vmax for. the same reaction is with the unit of . Be sure to give the values with the correct number of significant figures. You might have to construct a kinetic plot. For units, choose one answer from (uM, 1/ UM, HM/second, uM x second, mM, 1/mM, second, 1/second, mM/second, mM x second) vo (mM/sec) Glucose concentration (mm) 0.10...
help with b) please
3. Use we wyl Reaction rate (mol/min) (Substrate] Substrate Substrate + Unknown 1/[Substrate) 1N 1N (s. wow (UM) 0,055 0.1 I I 18.19 10 (2.5 10.115 0.183 0.4 8.70 5.46 5 10.17 0. 25 0 .2 5.884 0.250 .306 0. 1 4 3.29 20 0.31 0.35 0.05 3.23 2.86 SIOPE (r-oris) 10 12 -0.4 02 00 02 04 06 08 substrate b) Find Km and Vmax. Show your work. 16
(15 points) The following data is for a reaction
catalyzed by tyrosine monoxygenase:
Substrate
Concentration
(mol/L)
Initial Velocity (mM/min)
1.5
0.66
1.2
0.65
0.81
0.45
0.65
0.39
0.49
0.32
0.27
0.21
a) Plot the velocity (y-axis) versus substrate
concentration [S] (x-axis) curve and insert/draw the graph in the
space below. What are the approximate KM and
Vmax values?
b) Construct a 1/v (y-axis) versus 1/[S]
(x-axis) plot in the space below. Calculate the KM and
Vmax values.
c) Calculate the...
1. The turnover number for an enzyme is known to be 5000 min. From the following set of data, calculate the Km, Vmax and the amount of enzyme present in this experiment. Use excel to obtain the lineweaver burk plot. Substrate concentration (MM) 1 Initial velocity (umol/min) 167 250 334 376 498 499 100 1,000
CHEM3250 Assignment-Enzyme Inhibition Consider the data below for an enzyme catalyzed reaction. The rate of the reaction has been determined with and without an inhibitor. A total concentration of enzyme of 20 uM was used in the experiment. SHOW WORK AND UNITS!!! Without Inhibitor With Inhibitor [substrate] (mM)Rate of formation of te of formation of product product (mM/min) mM/min) 6.67 5.25 0.49 7.04 38.91 1.0 2.2 6.9 41.8 44.0 1.5 3.5 1 a) On the same graph, plot the data...
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