a) Since the sample size is large (>30), the distribution of sample mean will be approximately normal.
Option C is correct.
b) P(Mean > 90.8)
= P(z > 1.95)
= 0.0256
c) P(Mean < 73.2)
= P(z < -2.45)
= 0.0071
d) P(78.6 < Mean < 90.2)
= P(-1.1 < z < 1.8)
= 0.8284
8.1.15-T Ra A simple random sample of size n 64 is obtained (a) Describe the sampling...
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