Java Programming.
please give me answer and explain in details.
In first screen shot with output have made changes only in equals method and in second code screen shot i have made changes in both hashcode and equals method please have a look
Output:
in above output: hascode for t[0] and t[1] is same because they both are referencing to the same object.
hashcode for t[1] and t[2] should be same but its not because we did not made changes in hashcode method in code of above screenshot.
hashcode of t[3] and string object will be diff because these are different objects
Second screen shot with changes in both equals and hashcode method:
Output:
Now we can see that the hascode for t[0] and t[1] and t[2] is same as t[0] and t[1] are pointing to the same object and t[1] and t[2] have same values for coeff and exp.
CODE with changes in both method:
public class Term{
private int coeff;
private int exp;
public Term (int coeff,int exp){
this.coeff=coeff;
this.exp=exp;
}
public int getCoeff(){
return coeff;
}
public int getExp(){
return exp;
}
@Override //we can put some more conditions in equals
method given by you ..changes made are given below
public boolean equals(Object obj){
if(obj==this){ // this condition is
to check whether the object refer to the same location like t[0]
and t[1] refer to the same object
return
true;
}
if(!(obj instanceof Term)){
return false; //
if we pass any other object other than Term will return false
}
Term term=(Term) obj;
return
((term.coeff==this.coeff)&&(term.exp==this.exp)); // here
we are checking the value of the object if these values are equal
it will return true
}
@Override
public int hashCode(){
int result= this.coeff * this.exp
*999; // after making changes in hashcode method
return result; // now for Term
object having same values will have same hashcode value
}
public static void main(String[] args){
Term[] t=new Term[4];
t[0] =new Term(1,2);
t[1] =t[0]; // t[0] and t[1] refers
to the same location so will give us same hashcode value
t[2] =new Term(1,2);
t[3] =new Term(3,4);
String str=new String("abc");
System.out.println("checking equals
method :"+t[0].equals(t[2]));//here we are checking equals method
it should return true and now hashcode for both will be same
// because we have made changes in
hashcode method now.
for(int i=0;i<4;i++){
System.out.println("Hashcode for
object t["+i+"] : "+t[i].hashCode()); // printing hashcode values
for Term objects
}
System.out.println("Hashcode for
string object str : "+str.hashCode()); //printinh hashcode value
for string
}
}
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