I. Section 3.3 Solve using the substitution method. m-2n 16 4m + n = 1
using substitution method 5.m + 2n = 1 (When different variables than x and y are used, you go in alphabetical 5m + 3n = -23 order when writing the ordered pair: example: (a,b) (w, z) (m, n)
Solve the recurrence relation using a recursion tree AND substitution method: T(n) = 2T(n - 1) + 10n.
Solve the recurrence relation using a recursion tree AND substitution method: T(n) = T(n-1) + 10n
solve the recurrence relation using the substitution method: T(n) = 12T(n-2) - T(n-1), T(1) = 1, T(2) = 2.
Solve by using moment distribution method 28.904 26.856 16.257 16.257 KN/m 16.257 28.904 KN/m 26.856 KN(m 16-257 KN/m Nm Nm KNIm KNIM B 4.2m C 2.7mG 2.7mI 2.7m 2.7m M O Wh 4.2m 6m 4m E 6 m 6 m 6 un 6 m J A N ITTT Solve by using moment distribution method 28.904 26.856 16.257 16.257 KN/m 16.257 28.904 KN/m 26.856 KN(m 16-257 KN/m Nm Nm KNIm KNIM B 4.2m C 2.7mG 2.7mI 2.7m 2.7m M O Wh...
Solve the recurrence relation using iterative method subject to the basis step [13 points] s(1)=1 s(n)=s(n-1)+(2n-1),for n≥2 Then, verify the solution by using mathematical induction [7 points]
method: 1- Solve these recussion with substitution a) T (n)= T (2/2 ) tn 1. bi T (n) = 4T (M 2 ) +
solve these recurrences using backward substitution method: a- T(n)=T(3n/4)+n b-T(n) = 3 T(n/2) +n
By using a constructive method, prove that there is a positive integer n such that n! < 2n By using an exhaustive method, prove that for each n in [1.3], nk 2n. By using a direct method, prove that for every odd integer n, n2 is odd. By using a contrapositive method, prove that for every even integer n, n2 By using a constructive method, prove that there is a positive integer n such that n!
Problem 1. Solve the following simultaneous congruence using the Chinese Remainder or the substitution method. a: 2 (mod 5) a: 0 (mod 7) a: = 1 Problem 1. Solve the following simultaneous congruence using the Chinese Remainder or the substitution method. x = 2 (mod 5) x = 0 (mod 7) El mod 17)