Question

If 3.45 mol of an ideal gas has a pressure of 2.87 atm and a volume of 71.57 L, what is the temperature of the sample in degrees Celsius?

T = _______ ℃

Answer 1

NR Answer to the following question (n) mole number of an ideal gas = 3. 45 moles (P) Pressure of an ideal gas = 2.87 atm (v) Volume of an ideal gas = 71.57L R= Universal gas constant = 0.082 Larm. K-Imole! Ideal gas equation of a moles ideal gas PV = nRT [T&Temperature in Kelvin] .=) T = PV (2.87 atm.) * (71,57L). (3.45 moles) (0.082 Latm kol moles-') 205.4059 almxy 0.2829 moles x Yatim kl molest = 726•072k. (T- Temperature) = (726.072-273)°C [T€ =(T+2 73)] = 453.072°C Hence the temperature of the sample in de is equal to 453.072 °c