QUESTION 26 What is the mass, in grams, of one arsenic atom (NA- 6.022 x 1023...
3. What is the mass in grams of 6.022 x 1023 molecules of CO2? A. 22 g B. 44 g C. 668 D. 28 g
what is the mass (grams) of 6.022 x 1023 potassium atoms? - How many sodium atoms are there in 5.000 moles? How many sodium atoms are there in 100 narams of sodium?
Question 3 of 37 Determine the mass in grams of 3.52 1021 atoms of arsenic. (The mass of one mole of arsenic is 74.92 g. g 1 2 3 4 5 6 с 7 8 9 +/- 0 X 100 + 29 MacBc
1. One mole of sodium atoms contains: a) 23 atoms b) 6.022 x 1023 grams c) 6.022 x 1023 atoms d) 60.22 x 1023 atoms
What is the mass in grams of 1 atom of Na 1.661 * 10 ^ - 24 4.179 * 10 ^ - 26 1.931 * 10 ^ - 25 5.325 * 10 ^ - 23 3.82 * 10 ^ - 23
If 4.05 x 1023 molecules of a substance have a mass of 86.2 g, what is the molar mass of the substance? Multiple Choice 128 g/mol 3.49 1025 g/mol 0 2.13 * 1022 g/mol 4.70 * 1021 g/mol 58.0 g/mol
Determine the mass in grams of 3.00 x 10^21 atoms of arsenic. (The mass of one mole of arsenic is 74.92g.)
How many grams of Al are in 1.38 * 1023 molecules of Al2O3 if the atomic mass of Al is 27.0 g/mole, O is 16.0 g/mole, and Al2O3 is 102.0 g/mole (the final answer should have the correct number of significant figures)? Here is my work: (1.38*10^23 molecules) (1mol / 6.022*10^23 molecules) (27.0 gram/ mol)= 6.1873 I counted 3 Sig Fig so I rounded my answer to 6.19.... Another thought was (1.38*10^23 molecules) (54grams /1 mol) (1mol/6.022*10^23) but that answer...
6:39 < Question 6 of 10 Submit What is the mass in grams of KBr in 0.400 of a 0.350 M solution? STARTING AMOUNT ADD FACTOR ANSWER RESET 6.022 x 1023 0.350 0.400 M KBr 39.10 0.140 g KBr 16.7 mL 119 g KBr/mol 5.47 mol KBT 136 Tap here or pull up for additional resources
f. 6.022 X 1023 mol 2. Perform the following calculations and report your results to the correct number of significant figures a.212.2+26.77 402.09 6-1 b. 52.331 +26.01-0.998173 ande. (64,04-2.91)/(18.7-17)-11ae5F 24 d. (1.00866 -1.728)/(6.02205 x 10)- -1 195 Xlo e. (6.6262 x 1034, 2.998 x 108)/ (2.54 x 10°)- Lo 1,99745 x 10-25 3. Using dimensional analysis, perform the following conversions and report your results to the correct number of significant figures (centi 102; milli 10: micro 10; nano 10; pico...