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Using a forked rod, a smooth 3-lb particle is forced to move along around the horizontal path in the shape of a limaçon, r =
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Solution : Given; mass me 3-4b go (5+ Sino) ft o dt? xad {t is in seconds) at t= 3 sec, force of the rod (f) and normal force8 = [ şim(1.125x180) ()*]+[cas (1125x180)*(+)] = -0.507 +0:107 = -0.4.ft/s? tangent LLLLL G1-125xed radial acceleration 4 parIN= 0·3.47 3-16 TE fo = m.agi F-N Sin 4.18 = 3x1.95 32.2 F = 3X1.95 + CO-347) Sin 4-18 1. 32.2 P = 0.206 - eb

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