We know that the formula for the Buoyancy force is given by
Fb =ma+mg
pgV =ma+mg
pgV =m(a+g)
Then mass (m) =pgV/(a+g) =(1.16kg/m3)(9.81m/s2)(6*10-2m3)/(2.65m/s2+9.81m/s2)=0.054797kg
Now the mass of the air balloon is given by
m' =m -mp =0.054797kg -0.04kg=0.014797kg
Then the density of the gas consumer is (p) =mass/volume =0.014797kg/6*10-2m3=0.2466kg/m3
A consumer upset with the latest trend of postal rate increases has decided to try to...
A consumer upset with the latest trend of postal rate increases has decided to try to send letters by balloon even though they may not reach their intended destinations. A 6.00×104 cm3 gas-filled balloon will provide enough lift for a 45.1 g package to be accelerated upward at a rate of 2.95 m/s2 . For these circumstances, calculate the density of the gas the consumer fills the balloon with. The acceleration due to gravity is ?=9.81 m/s2 and the density...
A consumer upset with the latest trend of postal rate increases has decided to try to send letters by balloon even though they may not reach their intended destinations. A 79200 cm gas-filled balloon will provide enough lift for a 45.1 g package to be accelerated upward at a rate of 2.80 m/s. For these circumstances, calculate the density of the gas the consumer fills the balloon with. The acceleration due to gravity is g = 9.81 m/s2 and the...