A weight W hangs from two steel cables of equal length attached to each other as...
A weight W hangs from two steel cables of equal length attached to each other as shown. The combined length of both cables is 35 m. The cross section of upper cable is 20 mm2 whereas the cross section of the lower cable is 80 mm2. The Young's modulus of both cables is 200,000 N/mm2.
If the total extension of the combined cable is 4 mm, determine that value of the weight W in Newtons. Round off your answer to the nearest Newton.
Homework Answers
ANSWER:-
Given that
A weight W hangs from two steel cables of equal length attached to each other as shown.
The combined length of both cables is 35 m.
The cross section of upper cable is 20 mm^2
the cross section of the lower cable is 80 mm^2
The Young's modulus of both cables is 200,000 N/mm^2
the total extension of the combined cable is 4 mm,
![Wall < 3 180 total 1801 Apt 180) Be IPL / PLY LAE AB ILI CB 17.5 17.5 20 X 200000 80 x 200000 4 X 200000 ux200000 17.5% Got]](http://img.homeworklib.com/questions/ec96af90-6d97-11ec-acc8-0d71c03b2092.png?x-oss-process=image/resize,w_560)
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