Solution :
Given that ,
mean =
= 300
standard deviation =
= 50
n = 100
sample distribution of sample mean is ,
=
= 300
sampling distribution of standard deviation
=
/
n =50 /
100=5
= 5
sampling distribution is approximately normal with mean =300 and standard deviation =5
A random sample of size n = 100 is obtained from a population with fl= 300...
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