Question

Can some one please help me with this problem based on cryptography except let p= 521 and a=3 i need help as soon as possibles thanks in advance

8.5. Compute the two public keys and the common key for the DHKE scheme with the parameters p 467, a 2, and 1. a-3,b-5 2. a 400, b 134 3. a-228, b-57 In all cases, perform the computation of the common key for Alice and Bob. This is also a perfect check of your results.

Answer 1

α mod ub,q 3 2 mod 46 - a mod 5 32 pub,b mod mod b,a) Step -Accumulated ResultBinary exponent Cs Scannet wit CamScanner

400 2' mod 464 StepAccumated Result Binary Exponent 2 612 12 2 1001 1100 O CIST. 225 mod AG パ00100 1 100,000 110010000 (189)" = 229 mod ų641 (2292三 134 mod ų64 | 2. (400o 400 b,a2 mod 461 pu a 131 3Y 2- mod 64 Scanned with CS mSca13,-

epclated Result Binary Exponent- 2x 22 mod u6H 2 H 16 25 mod(l000), 256) 156 mod H6(100oo 2 (102 150 mod u6j(100001 8.(1508u mod 6(1000010 134 13 4) mod 4 (10000110)2 CS Scanned 342,- to CamScanner

an-Accumulated esult einart_Fpor ent Exbonent 84)- 51 mod 464. to 4. | (266's 239 mod u64 ( 5. | (239)2= ,HA mod u63 | G. | (147)2x84 Ξ 3ay rood 464 | (1000)2 (10000)2 (100001), 000o11 8. (250389 mod H63 (134 0 13u) lo 134 KAR 4 mod 467 pub.ad p 228 mod 464 (11100100 ) (22%) Cs Scanned wit CamScanner

Step Accumulated Result inar aponent (11)2 (111)2 (1110)2 82x2三128 mod 464 (128) h. 5 G. 39 mod 463 (a)2Ξ 120 11100 (120)2x2ニろ13 (313266 mod 6(I11000), mod 46-1 sau mod h6tC110010o) 228 228 pub.a mod 46 39H α mod 51 2,, mod 464 E 313 (394)53 mod 464 트 Cs Scanned with CamScanner