Given that, the null and the alternative hypotheses are,
Using TI-84 calculator we get,
a) Test statistic is, z = 2.89
b) Since, it is right-tailed test,
p-value = P(Z > 2.89) = 1 - P(Z < 2.89)= 1 - 0.9981 = 0.0019
=> p-value = 0.0019
c) with
p-value is less than , so we reject H0
Consider the following hypothesis test Но The following results are for two independent samples taken from...
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