Show that A*(BxC) = B*(CxA) = C*(AxB) Using the Levi Civita symbol (A,B,C are all vectors).
a=4i + k Calculate the vector product axb Check that a x b is normal to a and to b Calculate exd and lexd Find a unit vector normal to the plane of the vectors b and d b- 2i-3j-k d--i+2j+k
QUESTION 7 t0 points Factors A, B, C D, E and interactions AxB, AxC, AxD, AxE, BxC, BxD, BxE CxD, CxE, DxE a. L4 b.L8 dL16 10 points QUESTION & DxE) how many columns minimum would be required (based on the L'n formulal) Oa 13 b.18 O d. 10 points QUESTION 9 n True True O False 10points QUESTION 10 QUESTION 7 t0 points Factors A, B, C D, E and interactions AxB, AxC, AxD, AxE, BxC, BxD, BxE CxD,...
Given vectors A = 3i -2j +k and B = 4i + 2j - 5k, find the angle between them. A car slows down from a speed of 60 mph to rest in 10 s, How far did it travel in that time?
Find ▽f(x) and ▽2f(x) f(X) bXc, where X E RnXn and b, c E R". - 0AC. where Find ▽f(x) and ▽2f(x) f(X) bXc, where X E RnXn and b, c E R". - 0AC. where
If A = 21-j-k. B=2i-Sj-k, C = j + k, find (A-B)C. A(B-C), (AxB)-C, A.(B × C). (A × B) × C, A × (B × C) 1.
D Question 1 Question 1 Let A (5,-2, 6), B (5.-9,3), C (3.-4. 1) be three points. i) Calculate the vectors a = BC and b = CA ii) Calculate (axb) and (axb): a Formulae: x → cross product . + dot product j K axb= a1 a2 a3 b, b₂b3 a.b=019223 + b b2b3 Algebraic form
#8 8. What is the cross product of the vectors A=-31 +3j -4k and B=4i +2j+k. What is the angle between A and B? 9. What is the scalar product of the vectors A= i +3j -2k and B= i +6j + 3k. What is the angle between A and B? 10. What is the scalar product of the vectors A= -31 +3j -4k and B=41 +2j+ k. What is the angle between A and B? 11. Find the area...
1. Given the following 3 vectors, evaluate a. 2A+B b. C-A c. 2BXC-omit d. C-(AXB) - Ort A = 2i - 13 + 4k B=4i + ij - 5k C = -2i+2j – 3k = 120 at 450 - 200 at 1260 Find D E 2. The position of an object is related to time by X = Ata--Bt + C, where A -6m/s?.
Prove the following vector identity using index notation A X (BXC) = (A.C)B - (A.B)C