The population of wolves in Eastern Washington is 3000 and is increasing at a rate of...
The population of wolves in Eastern Washington is 3000 and is increasing at a rate of 4.5% per year. Let t represent years and f(t) represents the population of wolves an any time t. (a) Write the exponential function that models the wolves’ population (b) What is the population in 7 and 14 years?
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The population of wolves in Eastern Washington is 3000 and is
increasing at a rate of...
Scientists studying a population of wolves (y), and a population of rabbits (x) on which the...
Scientists studying a population of wolves (y), and a population of rabbits (x) on which the wolves depend for food, have found the sizes x and y of these populations to be modeled well by the equation 4 Iny -0.02y +3 In x -0.001x = 37.37 P(5000,300) wolves [The equation is graphed at right. Point P(x, y) moves around the curve in the direction shown as x and y variously increase and decrease in what is known as a predator-prey...
A population of a certain species of turtle is 28,000 animals and is increasing at the...
A population of a certain species of turtle is 28,000 animals and is increasing at the rate of 2% per year. This paragraph describes a(n) Select an answer linear growth linear decay exponential growth exponential decay scenario. Write an equation for y, the population at time t (in years), representing the situation. y = How many turtles are in the population after 15 years?
the population of a city was 5 45 million. The exponential growth rate was 2 64%...
the population of a city was 5 45 million. The exponential growth rate was 2 64% per year. a Find the exponential growth function b Estimate the population of the city in 2018 c) When will the population of the city be 7 million? d) Find the doubling time. a) The exponential growth function is P(t)# where t is in terms of the number of years since 2012 and Type exponential notation with positive exponents Do not simplity Use integers...
In 2012, the population of a city was 629 million. The exponential growth rate was 3.41%...
In 2012, the population of a city was 629 million. The exponential growth rate was 3.41% per year. a) Find the exponential growth function. b) Estimate the population of the city in 2018 c) When will the population of the city be 8 million? d) Find the doubling time a) The exponential growth function is P(t)wher t is in terms of the number of years since 2012 and P() is the population in millions. (Type exponential notation with positive exponents....
In 2012, the population of a city was 5.42 million. The exponential growth rate was 1.75%...
In 2012, the population of a city was 5.42 million. The exponential growth rate was 1.75% per year. a) Find the exponential growth function. b) Estimate the population of the city in 2018 c) When will the population of the city be 9 million? d) Find the doựbling time a) The exponential growth function is (t) = where t is in terms of the number of years since 2012 and P(t) is the population in millions (Type exponential notation with...
The fox population in a certain region has a continuous growth rate of 9 percent per...
The fox population in a certain region has a continuous growth rate of 9 percent per year. It is estimated that the population in the year 2000 was 8300. (a) Find a function that models the population t years after 2000 (t = 0 for 2000). Hint: Use an exponential function with base e. Your answer is P(t) = (b) Use the function from part(a) to estimate the fox population in the year 2008. Your answer is the answer must...
In 2012, the population of a city was 5.82 million. The exponential growth rate was 2.28%...
In 2012, the population of a city was 5.82 million. The exponential growth rate was 2.28% per year. a) Find the exponential growth function. b) Estimate the population of the city in 2018. c) When will the population of the city be 8 million? d) Find the doubling time. a) The exponential growth function is P(t) = , where t is in terms of the number of years since 2012 and P(t) is the population in millions. (Type exponential notation...
In the year 2000, the population of a certain country was 276 million with an estimated growth rate of 0.5% per year a. Based on these figures, find the doubling time and project the population in 21...
In the year 2000, the population of a certain country was 276 million with an estimated growth rate of 0.5% per year a. Based on these figures, find the doubling time and project the population in 2120 b Suppose the actual growth rates are ust 0.2 percentage points lower and higher than 0.5% per year 0.3% and 0.7%). What are the resulting doubling times and projected 2120 population? a. Let y(t) be the population of the country, in millions, t...
1) Please write clearly. In 2012, the population of a city was 5.97 million. The exponential...
1) Please write clearly.
In 2012, the population of a city was 5.97 million. The exponential growth rate was 1.66% per year. a) Find the exponential growth function. b) Estimate the population of the city in 2018. c) When will the population of the city be 10 million? d) Find the doubling time. a) The exponential growth function is P(t) = 1, where t is in terms of the number of years since 2012 and P(t) is the population in...
In the year 2000, the population of a certain country was 278 million with an estimated...
In the year 2000, the population of a certain country was 278 million with an estimated growth rate of 0.5% per year. Based on these figures, find the doubling time and project the population in 2100. Let y(t) be the population of the country, in millions, t years after the year 2000. Give the exponential growth function for this country's population. y(t) = 1 (Use integers or decimals for any numbers in the expression. Round to four decimal places as...
Scientists studying a population of wolves (y), and a population of rabbits (x) on which the wolves depend for food, have found the sizes x and y of these populations to be modeled well by the equation 4 Iny -0.02y +3 In x -0.001x = 37.37 P(5000,300) wolves [The equation is graphed at right. Point P(x, y) moves around the curve in the direction shown as x and y variously increase and decrease in what is known as a predator-prey...
the population of a city was 5 45 million. The exponential growth rate was 2 64% per year. a Find the exponential growth function b Estimate the population of the city in 2018 c) When will the population of the city be 7 million? d) Find the doubling time. a) The exponential growth function is P(t)# where t is in terms of the number of years since 2012 and Type exponential notation with positive exponents Do not simplity Use integers...
In 2012, the population of a city was 629 million. The exponential growth rate was 3.41% per year. a) Find the exponential growth function. b) Estimate the population of the city in 2018 c) When will the population of the city be 8 million? d) Find the doubling time a) The exponential growth function is P(t)wher t is in terms of the number of years since 2012 and P() is the population in millions. (Type exponential notation with positive exponents....
In 2012, the population of a city was 5.42 million. The exponential growth rate was 1.75% per year. a) Find the exponential growth function. b) Estimate the population of the city in 2018 c) When will the population of the city be 9 million? d) Find the doựbling time a) The exponential growth function is (t) = where t is in terms of the number of years since 2012 and P(t) is the population in millions (Type exponential notation with...
The fox population in a certain region has a continuous growth rate of 9 percent per year. It is estimated that the population in the year 2000 was 8300. (a) Find a function that models the population t years after 2000 (t = 0 for 2000). Hint: Use an exponential function with base e. Your answer is P(t) = (b) Use the function from part(a) to estimate the fox population in the year 2008. Your answer is the answer must...
In 2012, the population of a city was 5.82 million. The exponential growth rate was 2.28% per year. a) Find the exponential growth function. b) Estimate the population of the city in 2018. c) When will the population of the city be 8 million? d) Find the doubling time. a) The exponential growth function is P(t) = , where t is in terms of the number of years since 2012 and P(t) is the population in millions. (Type exponential notation...
In the year 2000, the population of a certain country was 276 million with an estimated growth rate of 0.5% per year a. Based on these figures, find the doubling time and project the population in 2120 b Suppose the actual growth rates are ust 0.2 percentage points lower and higher than 0.5% per year 0.3% and 0.7%). What are the resulting doubling times and projected 2120 population? a. Let y(t) be the population of the country, in millions, t...
1) Please write clearly.
In 2012, the population of a city was 5.97 million. The exponential growth rate was 1.66% per year. a) Find the exponential growth function. b) Estimate the population of the city in 2018. c) When will the population of the city be 10 million? d) Find the doubling time. a) The exponential growth function is P(t) = 1, where t is in terms of the number of years since 2012 and P(t) is the population in...
In the year 2000, the population of a certain country was 278 million with an estimated growth rate of 0.5% per year. Based on these figures, find the doubling time and project the population in 2100. Let y(t) be the population of the country, in millions, t years after the year 2000. Give the exponential growth function for this country's population. y(t) = 1 (Use integers or decimals for any numbers in the expression. Round to four decimal places as...
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