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During the first 13 weeks of the television season, the Saturday evening 8:00 p.m. to 9:00...

During the first 13 weeks of the television season, the Saturday evening 8:00 p.m. to 9:00 p.m. audience proportions were recorded as ABC 29%, CBS 28%, NBC 25%, and independents 18%. A sample of 300 homes two weeks after a Saturday night schedule revision yielded the following viewing audience data: ABC 95 homes, CBS 70 homes, NBC 89 homes, and independents 46 homes.

Test with α = 0.05 to determine whether the viewing audience proportions changed.

State the null and alternative hypotheses.

H0: pABC = 0.29, pCBS = 0.28, pNBC = 0.25, pIND = 0.18 Ha: pABC ≠ 0.29, pCBS ≠ 0.28, pNBC ≠ 0.25, pIND ≠ 0.18

H0: The proportions are not pABC = 0.29, pCBS = 0.28, pNBC = 0.25, pIND = 0.18.
Ha: pABC = 0.29, pCBS = 0.28, pNBC = 0.25, pIND = 0.18    

H0: pABC ≠ 0.29, pCBS ≠ 0.28, pNBC ≠ 0.25, pIND ≠ 0.18
Ha: pABC = 0.29, pCBS = 0.28, pNBC = 0.25, pIND = 0.18

H0: pABC = 0.29, pCBS = 0.28, pNBC = 0.25, pIND = 0.18
Ha: The proportions are not pABC = 0.29, pCBS = 0.28, pNBC = 0.25, pIND = 0.18.

Find the value of the test statistic. (Round your answer to three decimal places.)

Find the p-value. (Round your answer to four decimal places.)

p-value =

State your conclusion.

Reject H0. There has not been a significant change in the viewing audience proportions.

Reject H0. There has been a significant change in the viewing audience proportions.    

Do not reject H0. There has not been a significant change in the viewing audience proportions.

Do not reject H0. There has been a significant change in the viewing audience proportions.

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Answer #1

H0: pABC = 0.29, pCBS = 0.28, pNBC = 0.25, pIND = 0.18

Ha: The proportions are not pABC = 0.29, pCBS = 0.28, pNBC = 0.25, pIND = 0.18

The following table is obtained:

Categories Observed Expected (fo-fe)2/fe
Category 1 95 300*0.29=87 (95-87)2/87 = 0.736
Category 2 70 300*0.28=84 (70-84)2/84 = 2.333
Category 3 89 300*0.25=75 (89-75)2/75 = 2.613
Category 4 46 300*0.18=54 (46-54)2/54 = 1.185
Sum = 300 300 6.867

value of the test statistic. = 6.867

The P-Value is .0763

p value > l.o.s

i.e., 0.0763 > 0.05

so fail to reject H0

Do not reject H0. There has not been a significant change in the viewing audience proportions.

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