Question

A block of mass 5 kg is attached to an ideal spring of spring constant 30 N/m on a frictionless horizontal surface. The spring is attached to a wall orn the other end. The block is moved 5 cm away from the equilibrium position of the spring such that the spring is stretched and then, it is let go. How long will it take for the block to come to a momentary stop at the other end? a) 2.565s b) 0.817s c) 1.283 s d) 0.408s through a nine (radius 1cm) suc

Answer 1

By energy conservation 1/2 kx^2 = 1/2 mv^2 v = x squareroot k/m = 0.05 squareroot 30/5 = 0.1224 m/s V = u + at V = 0, U = 0.1224 m/s and a = F/M = Kx/M = 30 times 0.05/5 = 0.3 m/s^2 so t = u/d = 0.1224/0.3 = 0.408 sec