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A block of mass m = 0.57 kg is attached to a spring with force constant...

A block of mass m = 0.57 kg is attached to a spring with force constant 144.0 N/m. The block is free to move on a frictionless, horizontal surface as shown in the figure. The block is released from rest after the spring is stretched a distance A = 0.16 m to the right. What is the potential energy of the spring/block system 0.20 s after releasing the block?

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Answer #1

Potential energy of system = L K (x=x3) eso at t=0, x=0 at t= 0.205, K₂ = 0.16m. given , k = 144 N/m eso Potential Energy = 4

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