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A block of mass m = 2.00 kg is attached to a sprin

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Answer #1

a)

Work required to stretch = Spring potential energy = (0.5) k x2 = (0.5) (455) (0.0565)2 = 0.7262 J

b)

using conservation of energy

Kinetic energy of block = spring potential energy = 0.7262

(0.5) m v2 = 0.7262

(0.5) (2) v2 = 0.7262

v = 0.852 m/s

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