Question

Write a program in C that meets the following requirements:
1. Your program will read n + 1 integers from the keyboard where n is the first integer read.

2. If n is less than 1 print an error message and return a status of 1.

3. If there are no positive numbers, print “no positive numbers”. This is not an error.

4. If there are positive numbers, print the average of the positive numbers.

5. 0 is neither positive or negative.

6. Do not print anything other than what is required.

Answer 1

Answer :

#include<stdio.h>
#include<stdlib.h>

int main()
{

//Declare and initialize all the variables which are used in the code.
int n,i,a[1000],status,count=0,count1=0,count2=0;
float b,avg=0;

//Read the input size n
printf("Enter the value of n\n");
scanf("%d",&n);

//check whether it is less than 1.

if(n<1) {
   printf("Error found\n");
   status = 1;
   return status;
}

//Read n+1 integers.

printf("Enter n+1 Integers\n");
for(i=0;i<=n;i++) {
   scanf("%d",&a[i]);
}

//Check each integers as below

for(i=0;i<=n;i++) {

//if integer is less than 0 increment count
if(a[i]<0) {
count++;
}

// if integer is greater than 0 positive one then increment count1
else if(a[i]>0) {
count1++;
b=b+a[i];
}

// if integer is 0 then increment count2
else {
count2++;
}
}

//Check whether all integers are 0

if(count2==n+1){
printf("0 is neither positive nor negative\n");
}

//check whether all integers are negative
if(count ==n+1){
printf("no positive numbers\n");
}

// check if positive integer is present then find the average
if(count1 >0) {
avg = b/count1;
printf("Average of positive numbers = %f\n",avg);
}
}

Output :