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Here we leam how to apply the force shown in the figure (Figure 1) moves an object nz0 to z 0.75 m. You may want to review ge incase you can’t see the question, it says : How much work is done by the force if the object moves from x= 0.15m to x= 0.60m?

(express your answer using two significant figures)
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Answer #1

Use equation,

W= F*d

Wnet = Wfrom 0.15m to 0.25m + Wfrom 0.25m to 0.50m + Wfrom 0.50m to 0.60m

Wnet = F1d1 + F2d2 + F3d3

Wnet = 0.6N*(0.25m-0.15m) + 0.4N*(0.50m-0.25m)*0.8N*(0.60m-0.50m)

Wnet = 0.24 J

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