To understand the cause of constructive and destructive interference for the double-slit experiment, and to explain how the interference pattern depends on the parameters of the emitted waves.
For this tutorial, use the PhET simulation Wave Interference. This simulation allows you to send waves through a variety of barriers and look at the resulting interference patterns.
Start the simulation. You will see three possible selections: Waves, Interference, and Slits. To change between simulations at any point, select the desired simulation on the toolbar located at the bottom of the screen. In these simulations you can choose between water waves, sound waves, or light. You can adjust the slit width and slit separation using slider bars, and you can put a barrier containing one or two slits in front of the source of the waves. There are also several measuring tools at the upper-right hand corner of the screen, including a detector that produces plots showing the wave amplitude vs. time for the location of the two sensors on the detector, which can be dragged to any location.
Feel free to experiment with all of the simulations to get a feel for how they work. When you are done, and before starting Part A, set the simulation to Waves, and select the Reset icon.
Part A
Select Light for the type of wave, adjust the wavelength so that the light is red, and increase the amplitude of the light to the max. Then, select the start button at the source location to begin producing the waves.
Light is a form of electromagnetic wave, containing oscillating electric and magnetic fields. The wave amplitude detector mentioned above shows how the electric field oscillates in time at the location of the probe. The amplitude of the wave at the location of the probe is equal to the maximum electric field measured.
How does the amplitude of the wave depend on the distance from the source?
The amplitude decreases with distance.
The amplitude increases with distance.
The amplitude is constant.
Relationship between distance and intensity (the inverse square law, I ∝ 1/d2), this implies amplitude is inversely proportional to distance .... thus, with increase in distance amplitude of the wave decreases
To understand the cause of constructive and destructive interference for the double-slit experiment, and to explain...
In a double-slit experiment, the slits are illuminated by a monochromatic, coherent light source having a wavelength of 697 nm. An interference pattern is observed on the screen. The distance between the screen and the double-slit is 1.67 m and the distance between the two slits is 0.104 mm. A light wave propogates from each slit to the screen. What is the path length difference between the distance traveled by the waves for the fifth-order maximum (bright fringe) on the...
In a double-slit experiment, the slits are illuminated by a monochromatic, coherent light source having a wavelength of 517 nm. An interference pattern is observed on the screen. The distance between the screen and the double-slit is 1.3 m and the distance between the two slits is 0.118 mm. A light wave propogates from each slit to the screen. What is the path length difference between the distance traveled by the waves for the fifth-order maximum (bright fringe) on the...
In a double-slit interference experiment the slit separation is 8.40 x 10-6 m and the slits are 2.80 m from the screen. Each slit has a width of 1.20 x 10-6 m. a) An interference pattern is formed when light with a wavelength of 450 nm is shined on the slits. How far (in meters) from the center of the interference pattern on the screen do the third order (m = 3) bright fringes occur? (1.5 pts) b) If a...
Question 3: Calibrating the Double Slit You are attempting to perform a double slit experiment (see Figure 2): the distance between slits is 0.1 mm, the distance from the barrier to the screen is L = 2 m, and the distance from the coherent) laser light source to the barrier is t = 0.4 m. You are using red light, with a wavelength = 660 nm. You are worried that you have not perfectly centred the laser halfway between the...
For a particular double-slit experiment, the slit separation is 4.50 μm, the screen is located 4.00 m from the slits, and the wavelength of the light illuminating the slits is 580 nm (yellow). You have a detector located on the screen at a distance of 20.5 cm from the center of the interference pattern. (a) Where in the pattern is this point located – at a minimum, maximum or in-between? Give the m values associated with this position (e.g. at...
A double-slit interference experiment is performed with two very narrow slits separated by 0.19 mm. The experiment uses red light with a wavelength of 700 nm and projects the interference pattern onto a screen 5.0 m away from the slits. (a) What is the distance between two nearby bright fringes on the screen? (b) What is the distance between two nearby dark fringes on the screen? Assume these fringes are all near θ = 0. A Young's double-slit interference experiment...
In a double-slit experiment, light with a wavelength λ passes through a double-slit and forms an interference pattern on the screen at a distance L from the slits. What would happen to the distance between maxima, if the frequency of the light increases?
A double-slit interference experiment is performed with two very narrow slits separated by 0.10 mm. The experiment uses red light with a wavelength of 680 nm and projects the interference pattern onto a screen 6.0 m away from the slits (a) What Is the dlstance between two nearby brlght fringes on the screen? (b) What is the distance between two nearby dark fringes on the screen? Assume these fringes are all near0
In a double-slit interference experiment, the wavelength is a = 702 nm, the slit separation is d = 0.160 mm, and the screen is D = 32.0 cm away from the slits. What is the linear distance Ax between the eighth order maximum and the third order maximum on the screen? Ax = mm
In a double‑slit interference experiment, the wavelength is ?=662 nm , the slit separation is ?=0.110 mm , and the screen is ?=50.0 cm away from the slits. What is the linear distance Δ? between the sixth order maximum and the fifth order maximum on the screen?