Question

1. Butane (CH..) burns with air, giving products having the dry molar analysis 11.0% CO., 1.0% CO 3.5% Oz. 84 59 Ns. The percent theoretical air is op Hlo alcant lot.3507845 a. 115% b. 110% c. 125% none He+,-

Answer 1

Jalu : Dory molar analysis - 11% CO2;'co; 3.5°/002, 84- 5 N2 Writing the combustion reaction:- a C4Hio + 6( 02+ 3.76 N2) ► 11 202 + {co + 3-5 02 + 84-5 N2 + CHLO Carbon balance - 498 11 + 2 a = 3 Hydrogen balance :- do a = 2c 302 20 ㅕ 15 oxygen balance : 20 = 22+1+7+ c > b= 22-5 balanced equation is - 3 C4H10 + 22-5 (Q2+ 3-76 N2) ► 11 CO2 + 100 + 3.502 + 84.5 N2 + 15 H20 A = - 22-5 x 4.76 Molen of ant Moled of fuel = 35.7

with theoretical amount of air? Ca Hiota (%2+3.76 N2) b Co2+ CH₂O + 3.76 a N2 Carbon balance . b = 4 Hydrogen balance - 20=10 CE5 Oxygen balance: 29 = 26+0 = q = 6-5 C4Hlo + 6-5 02 + 3-76N) -> 4 Co, + SHO+ 3-76 (6.5) N2 . (AF) theoreticad = 6-5x4.76 = 30-34 .: 0%. Theoretical air = - X 100 (AF) theoretical 35-7 - Xloo 30-94 % Theoretical air = 115 %