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EXPLAIN PLEASE! 10. Based on solubility rules, which reagent could be used to separate Br from...
What reagent could be used to separate Br- from SO42- when added to an aqueous solution containing both? A) CuSO4(aq) B) AgNO3(aq) C) Nal(aq) D) BA(OH)2(aq)
What reagent could not be used to separate Br from C032 when added to an aqueous solution containing both ions. Ca(NO3)2(a) None of these could be used to separate Brand CO 2 Cu(NO3)2(aq) Fe(NO3)2(aq) AgNO3(aq)
16) Write a balanced net ionic equation for the reaction of H2SO4iag) with Ba(OH)2(g) A) Ba2+(ag) + SO42-(a)- BaSO4) B) 2 H+(aq) SO42-(a) Ba2 (ag) +2 OH-(a)-BaSO4(0 2 H20) C) H2SO4(a) + Ba(OH)2(e) - BaSO40) 2 H20() D) H (ag) OH(ag)--H2O) 16) 17) Write a balanced net ionic equation for the reaction of Pb(NO3)2(ag) with Nal(ag). A) Pb2 (ag)+2 NO3-(4g) +2 Na+ (ag) +2 1-(a4)-- Pb2+(ag)+ 2 1-(a4)+ 2 Na (a) +2 NO3-(a) B) Pb2+(ag) 2 NO3-(a) + 2 Na...
can you please explain the answers 9. Based on the solubility rules, which one of the following compounds should be insoluble in water? A) Na2SO4 B) BaSO4 C) CuSO4 D) MgSO4 E) Rb2SO4 10. Identify the reducing agent in the following chemical reaction. Cd + NiO2 + 2H2O → Ca(OH)2 + Ni(OH)2 A) Cd B) Ni02 C) HO D) Ca(OH)2 E) Ni(OH)2 11. The oxidation number of Cl in CIO3 is A) -1 B) +7 D) +3 E) None of...
Based on the solubility rules which precipitate should form from this unbalanced equation? . Fe(NO3)3 + NalO 3 - ? A. Fe(103)3 B. FelO3 C. NaNO3 D. FeNaz ОА OB OD Based on the solubility rules which precipitate should form from this unbalanced equation? Cu(NO3)2 + Na2CO3 -? A. NaNO3 B. CuCO3 B. Cucos C. Cu2CO3 Di D. No precipitate forms OB OA oc OD Based on the solubility rules which precipitate should form from this unbalanced equation? AgNO3 +...
4. Using the table below which give the solubility rules for ionic compounds, predict whether each of the reactions below will produce a precipitate and, if so, what is the precipitate. If there is more than one precipitate, write down both of them. (2 points per reaction, 10 points total) Table 1 Solubility Rules for lonic Compounds Soluble in Water Insoluble in Water Any salt with Li+, Na+, K+, NH4+, NO3- Most chlorides, C oblava a AgCl, PbCl2, and HgCl2...
need to use solubility table to see if something solidifies/precipitates. I need help with figuring out which challenge reagents precipitate when reacting with the mixtures listed there. Ty!! For this exercise, let's say that you begin with an aqueous mixture containing the following compounds: Ba(NO3)2, Mg(NO3)2, and AgNO3 You also have separate solutions, one of each: K2SO4 (aq), KCI (aq), and KOH(aq) Let's call these the challenge reagents. Your task is to propose a step-by-step procedure for sequentially separating the...
Solubility Rules TABLE 1: SOLUBILITY RULES FOR CATIONS Precipitating agent lons that will form a precipitate Cl", Br", Agt, Pb2+, and Hg22 Ca2+, Sr2+, Ba2+, Agt, and Pb2+ All metal ions (with widely varying Ksp values) except Li, Na+, K+, and NHA All metal ions except Lit, Na, K, NH4+, Ca?, Srl, and Ba? CO32- All metal ions except Lit, Na, K, and NHA PO43- All metal ions except Lit, Na, K, and NH4 50,2- OH S2- Pre-Lab Questions 1....
please help me with these 2 questions A scientist adjusts the pH of a solution to prevent the precipitation of solid Fe(OH)2 in an aqueous solution of 0.0010 M Fe(CIO3)2(aq). What is his target pH? Ksp, Fe(OH), = 1.8 x 10-15 5. Solid AgNO3 is added in tiny amounts to a 1.00-L solution containing 0.10 M NaCl, 0.10 M NaBr, and 0.10 M Nal. Given: Ksp.Agci" 1.6 x 10-10, Ksp.AgBr - 5.0 X 10-13. Kapagi - 15 10-16 Which silver...
in the table below, predict which of the following reactant combinations will produce precipitates and write all the products that form (including states of matters- l, s, aq, g; write "ss" if it is slightly soluble). Useful information is also below. TABLE 4.1 | Simple Rules for the Solubility of Salts in Water 1. Most nitrate (NO3-) salts are soluble. 2. Most salts containing the alkali metal ions (Li+, Na+, K+, Cst, Rb+) and the ammonium ion (NH4+) are soluble....