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The two pendulums in the figure below each consist
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Answer #1

Ignoring friction, the size of the bob (ball) is irrelevant; the length matters though, since the period of a pendulum varies as

P=2 pi sqrt[L/g] where L is the length of the pendulum

therefore, the longer the pendulum, the longer the period

A has a pendulum that is twice as long, therefore its period will be sqrt(2) or 1.414 times longer than pendulum B

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