21. Two 500 g blocks of wood are 2.0 m apart on a frictionless table. A...

Question

Question

21. Two 500 g blocks of wood are 2.0 m apart on a frictionless table. A 30 g bullet is fired at 500 m/s toward the blocks. It

Answer 1

Answer #1

Using law of conservation of momentum,

m1u1 + m2u2 = m1v1 + m2v2

30 x 500 = 500 x 6 + 30 v2

V2 = 400 m/s

Again using law of conservation of momentum,

500 v1 + 0 = 30 x 400 + 0

Velocity, v1 = 24 m/s

Answer 2

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