Please show all steps The 90-kg wheel has a radius of gyration about its mass center...

Question

Question

The 90-kg wheel has a radius of gyration about its mass center (Figure 1) of ko = 400 mm. Part A Determine its angular veloci

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Answer 1

Answer #1

we know that Torque(T) = Moment of inertia(I) * Angular Acceleration(alpha)

Torque = 50*0.6 = 30Nm(radius of wheel* Force )

I = mass * radius of gyration²=90*0.4²=14.4 Kg m²

so 30 = 14.4 * alpha

alpha = 2.08333 rad/s²

now final angular velocity = initial angular velocity + alpha * time

starts from rest so initial angular velocity = 0

Final angular velocity = 2.08333*20= 41.66667 rad/s

Answer 2

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